(3x+1)(x+2)=3x^2+7x+2

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Solution for (3x+1)(x+2)=3x^2+7x+2 equation: 



(3x+1)(x+2)=3x^2+7x+2

We move all terms to the left:

(3x+1)(x+2)-(3x^2+7x+2)=0

We get rid of parentheses

-3x^2+(3x+1)(x+2)-7x-2=0

We multiply parentheses ..

-3x^2+(+3x^2+6x+x+2)-7x-2=0

We get rid of parentheses

-3x^2+3x^2+6x+x-7x+2-2=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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